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ABC is right angle triangle at C. Let BC...

ABC is right angle triangle at C. Let BC = a, CA = b, AB = c and Let 'P' be the length of perpendicular from C to AB. prove that `1/p^2 = 1/a^2 + 1/b^2`

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Area of triangle `ABC,(A)= 1/2**base**height = 1/2*a**b = (ab)/2`
As length of prependicular is `p` from `AB`,
`:.` Area `(A)= 1/2**c**p = (cp)/2`
`:. (ab)/2 = (cp)/2=> ab = cp`
`c = (ab)/p->(1)`
As `Delta ABC` is a right angle triangle,
`:. a^2+b^2 = c^2`
From (1),
...
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