In a right-angled isosceles triangle, the ratio of the circumradius and inradius is `2(sqrt(2)+1):1` (b) `(sqrt(2)+1):1` `2:1` (d) `sqrt(2):1`

In a right-angled isosceles triangle,the ratio of the circumradius and inradius is 2(sqrt(2)+1):1 (b) (sqrt(2)+1):12:1(d)sqrt(2):1

In a right-angled isosceles triangle, the ratio of the circumradius and inradius is (a) 2(sqrt(2)+1):1 (b) (sqrt(2)+1):1 2:1 (d) sqrt(2):1

The ratio between the circumradius and inradius of a right angled isosceles triangle is

The angles of a triangle are in the ratio, 1:2:7 . Prove that the ratio of the longest and smallest side is (sqrt(5)+1): (sqrt(5)-1) .

The perimeter of the triangle formed by the points (0,\ 0),\ (1,\ 0) and (0,\ 1) is 1+-sqrt(2) (b) sqrt(2)+1 (c) 3 (d) 2+sqrt(2)

The perimeter of the triangle formed by the points (0,0),(1,0) and (0,1) is 1+-sqrt(2) (b) sqrt(2)+1(c)3(d)2+sqrt(2)

In an isosceles right angled triangle ABC, /_B=90^0, AD is the median then (sin/_BAD)/(sin/_CAD) is (A) 1/sqrt(2) (B) sqrt(2) (C) 1 (D) none of these

In an isosceles right angled triangle ABC, /_B=90^0, AD is the median then (sin/_BAD)/(sin/_CAD) is (A) 1/sqrt(2) (B) sqrt(2) (C) 1 (D) none of these

If the equation of base of an equilateral triangle is 2x-y=1 and the vertex is (-1,2), then the length of the sides of the triangle is sqrt((20)/3) (b) 2/(sqrt(15)) sqrt(8/(15)) (d) sqrt((15)/2)

If the angles of a triangle are in the ratio 4:1:1, then the ratio of the longest side to the perimeter is (a) sqrt(3):(2+sqrt(3)) (b) 1:6 (c) 1:2+sqrt(3) (d) 2:3