A cyclist on the ground goes round a ciruclar path of circumference 34.3 m in `sqrt(22)` second. The angle made by him, with the vertical, will be:-

A cyclist goes around a circular track of circumference 410 m in 20 s. Find the angle that his cycle makes with the vertical.

A cyclist goes round a circular track of 440 metres length in 20 seconds Find the angle that his cycle makes with the verticle.

A cyslist goes round a circular path of length 4000 m in 20 second. Calculate the angle through which he bends from vertical in order to maintain the balance

Calculate the angle for which a cyclist bends when he turns a circular path of length 34.3 m in sqrt(22) s.

A cyclist goes round a circular path of radius 20.0 m with a speed of 14 m s^-1 .Find the angle through which his cycle makes with vertical. (g=9.8 ms ^-2) .

A cyclist moves around a circular path of radius 40sqrt3 m with a speed of 20 m//s . He must lean inwards at an angle theta with the vertical such that tan theta is equal to

A cyclist riding at a speed, of 24.25 ms^(-1) takes a round a circular road of radius 34.64 m. What is his inclination to the vertical ?

In the previous problem. If the bullet is moving with velocity 50 sqrt(2) m//s , the maximum angle made by string with vertical is

A motor cyclist going round on unbanked circular race course has to lean inwards, making an angle 21^(@) 49 ' with the vertical , in order to keep his balance. If the curve is 1 km long , then the speed of the cyclist will be, ( tan 21^(@) 49 =0.4003' g=9.8 m//s ^(2) )