Combustion fo glucose takes place according to the equation,`C_(6)H_(12)O_(6)+6O_(2)rarr6CO_(2)+6H_(2)O,DeltaH=-72kcal` How much energy will be required for the production of `1.6`g of glucose (Molecular mass of glucose=180g)

Combustion of glucose takes place according to the equation C_(6)H_(12)O_(6)+6O_(2) rarr 6CO_(2)+6H_(2)O, DeltaH=-"72 kcal/mol" . How much energy will be released by the combustion of 1.6 g of glucose (Molecular mass of glucose = 180 g/mol)?

Combustion of glucose takes place according to the equation C_(6)H_(12)O_(6)+6O_(2) How much rarr 6CO_(2)+6H_(2)O, DeltaH=-"72 kcal/mol" . energy will be released by the combustion of 1.6 g of glucose (Molecular mass of glucose = 180 g/mol)?

Find out the calorific value of Glucose C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O , Delta H=-2900 kJ/mole

Find out the calorific value of Glucose C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O , Delta H=-2900 kJ/mole

The equivalent weight of glucose in the reaction C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O is [M is molecular weight]

The heat envoled in the combustion of glucose is given by the equation C_(6)H_(12)O_(6(s))+6O_(2(g))rarr6CO_(2(g))+6H_(2)O_((g)) DeltaH=-680K.cal, The weight of CO_(2(g)) produced when 170 Kcal of heat is envolved in the combusation of glucose is