If the probability for A to fail in an examination is 0.2 and that for B is 0.3, then the probability that either A or B fails, is (A) 0.38 (B) 0.44 (C) 0.50 (D) 0.94

If the probabilities for A to fail in an examination is 0.2 and that for B is 0.3, then the probability that either A or B fails is

If the probabilities for A to fail in an examination is 0.2 and that for B is 0.3, then the probability that either A or B fails is

If the probabilities for A to fail in an examination is 0.2 and that for B is 0.3, then the probability that either A or B fails is

If the probabilities for A to fail in anexamination is 0.2 and that for B is 0.3, then the probability that either A or B fails is

If the probability for A to fail in one exam is 0.2 and that for B is 0.3 , then the probability that either A or B fails is

If the probability of X to fail in the examination is 0.3 and that for Y is 0.2, then the probability that either X or Y fails in the examination is

Observe the following statements : Statement-1 : The probabilities of the events A,B and C are respectively (2)/(3) , (1)/(4) and (1)/(6) then A,B,C are exhaustive Statement-2 : If the probability for A to fail in an examination is 0.2 and that for B is 0.3 then the probability that either A or B fails is 0.5 Statement-3 : If A and B are two independent events then P(AnnbarB)+P(A)P(B)=P(A) Which of the above are false