Locus of the image of the point `(1, 1)` in the line `(5x-2y-7) + lambda(2x - 3y +6)=0` (lambda in R`), is

Locus of the image of the point (1,1) in the line (5x-2y-7)+lambda(2x-3y+6)=0lambda in R, is

The locus of the image of the point (2,3) in the line (x-2y+3)+lambda(2x-3y+4)=0 is (lambda in R)( a) x^(2)+y^(2)-3x-4y-4=0 (b) 2x^(2)+3y^(2)+2x+4y-7=0(c)x^(2)+y^(2)-2x-4y+4=0(d) none of these

The locus of the image of the point (2,3) in the line (x-2y+3)+lambda(2x-3y+4)=0 is (lambda in R) (a) x^2+y^2-3x-4y-4=0 (b) 2x^2+3y^2+2x+4y-7=0 (c) x^2+y^2-2x-4y+4=0 (d) none of these

The locus of the image of the point (2,3) in the line (x-2y+3)+lambda(2x-3y+4)=0 is (lambda in R) (a) x^2+y^2-3x-4y-4=0 (b) 2x^2+3y^2+2x+4y-7=0 (c) x^2+y^2-2x-4y+4=0 (d) none of these

The locus of the image of the point (2,3) in the line (x-2y+3)+lambda(2x-3y+4)=0 is (lambda in R) (a) x^2+y^2-3x-4y-4=0 (b) 2x^2+3y^2+2x+4y-7=0 (c) x^2+y^2-2x-4y+4=0 (d) none of these

Locus of the image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0, k in R is a

Locus of the image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0 , k in R, is a

Locus of image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0 ,k in R is

Is there a real value of lambda for which the image of the point (lambda,lambda-1) by the line mirror 3 x + y = 6 lambda is the point (lambda^2 + 1, lambda) If so find lambda . ,

The equation of the locus of the foot of perpendicular drawn from (5, 6) on the family of lines (x-2)+lambda(y-3)=0 (where lambda in R ) is