(7+...+4p+0n" terms ")/(-8+11...10" terms ")=7," then the value of "n=

If (3+5+7+ . . . .+"n terms")/(5+8+11+ . . .. +"10 terms")=7 , then the value of n, is

If (3+5+7+... upto n terms )/(5+8+113... upto 10 terms )=7, then find the value of n.

if (3 +5+7+9+…. " up to 35 terms " )/(5+8+11+ …. " up to n terms ")=7 , find the value of n.

if (3+5+7...n terms)/(5+8+11+...10 terms)=7 find n.

If (5+9+13+...... n terms)/( 7 + 9 + 11 +....(n+1) terms) = 17/16 , then n=

If (5+9+13+..."upto n terms")/(7+9+11+..."upto 12 terms")=(5)/(12) , then n is equal to

[" If the ratio of the sum of "n" terms of two "],[" A.P.s is "(3n+8):(7n+15)" ,then the ratio "],[" of the "12],[" th term is "]

If a_(n) be the term of an A.P. and if a_(7)=15 , then the value of the common difference that could makes a_(2)a_(7)a_(11) greatest is:

If (1 + 3 + 5 + .... " upto n terms ")/(4 + 7 + 10 + ... " upto n terms") = (20)/(7 " log"_(10)x) and n = log_(10)x + log_(10) x^((1)/(2)) + log_(10) x^((1)/(4)) + log_(10) x^((1)/(8)) + ... + oo , then x is equal to