x log x(dy)/(dx)+y=(2)/(x)log x

Find the general solution of the differential equations: ,x log x(dx)/(dy)+y=(2)/(x)log x

Let y(x) be the solution of the differential equaiton : (x log x ) (dy)/(dx) +y=2x log x, (x ge 1) Then y(e) is equal to :

The solution of x log x (dy)/(dx) + y = 2/xlog x is

Let y(x) be the solution of the differential equation (x log x)(dy)/(dx)+y=2x log x,(x>=1) Then y(e) is equal to :(1)e(2)0(3)2(4)2e

The solution of x log x (dy)/(dx) + y = 2 log x is

Let y(x) be the solution of the differential equation ( x log x) (dy)/(dx) + y = 2x log x, ( x gt 1). then y (e ) is equal to :

Let y(x) be the solution of the differential equation ( x log x) (dy)/(dx) + y = 2x log x, ( x gt 1). then y (e) is equal to :

Let y(x) be the solution of the differential equation . (x log x) (dy)/(dx) + y = 2x log x, (x ge 1) . Then y (e) is equal to