[" The Conductivity of Saturated solution of "Ba_(3)(PO_(4))_(2)" is "1.2times10^(-5)Omega^(-1).cm^(-1)." The limiting equive "],[BaCl_(2),K_(3)PO_(4)" and "KCl" are "160,140" and "Omega^(-1)cm^(2)eq^(-1)" respectively.The solubility product "],[" temperature is "]

The conductivity of saturated solution of Ba_(3) (PO_(4))_(2) is 1.2 xx 10^(-5) Omega^(-1) cm^(-1) . The limiting equivalent conductivities of BaCl_(2), K_(3)PO_(4) and KCl are 160, 140 and 100 Omega^(-1) cm^(2)eq^(-1) , respectively. The solubility product of Ba_(3)(PO_(4))_(2) is

The conductivity of saturated solution of Ba_(3) (PO_(4))_(2) is 1.2 xx 10^(-5) Omega^(-1) cm^(-1) . The limiting equivalent conductivities of BaaCl_(2), K_(3)PO_(4) and KCl are 160, 140 and 100 Omega^(-1) cm^(2)eq^(-1) , respectively. The solubility product of Ba_(3)(PO_(4))_(2) is

The conductivity of saturated solution of sparinlgy soluble salt Ba_(3)(PO_(4)_(2) is 1.2 xx 10^(-5) ohm^(-) cm^(-1) . The limiting equivalent conductivities of BaCl_(2) , K_(3)PO_(4) and KCl are 160, 140 and 100 ohm^(-1) cm^(2) eq^(-1) respectively. If value of K_(sp) of Ba_(3)(PO_94))_(2) is A xx 10^(-25) then calcualte value of A//12

A saturated solution of Ca_(3)(PO_(4))_(2) has [Ca^(2+)]=2xx10^(-8) M and [PO_(4)^(3-)]=1.6xx10^(-5) M K_(sp) of Ca_(3)(PO_(4))_(2) is :

A saturated solution of Ca_(3)(PO_(4))_(2) has [Ca^(2+)]=2xx10^(-8) M and [PO_(4)^(3-)]=1.6xx10^(-5) M K_(sp) of Ca_(3)(PO_(4))_(2) is :

A saturated solution of Ca_(3)(PO_(4))_(2) has [Ca^(2+)]=2xx10^(-8) M and [PO_(4)^(3-)]=1.6xx10^(-5) M K_(sp) of Ca_(3)(PO_(4))_(2) is :

The conductivity of a saturated solution of Ag_(3)PO_(4) is 9xx10^(-6) Sm^(-1) and its equivalent conductivity is 1.50xx10^(-4) Sm^(-2) equivalent ^(-1) .

The conductivity of a saturated solution of a sparingly soluble salt MX_2 is found to be 4 xx 10^(-5) Omega^(-1) cm^(-1)." If "lambda_(m)^(oo) ( M^(2+))=50 Omega^(-1) cm^(2) mol^(-1) and lambda^(oo) (X^(-))= 50 Omega^(-1) cm^(2) mol^(-1) , the solubility product of the salt is about

The molar conductivity of 0.05 M BaCl_(2) solution at 25^(@)C is 223 Omega^(-1)"cm"^(2) mol^(-1) . What is its conductivity?