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A chord of a circle of radius 15cm subte...

A chord of a circle of radius 15cm subtends an angle of `60^@` at the centre.Find the area of corresponding major and minor segments of the circle. (Use `pi=3.14` and `sqrt3=1.73`)

Text Solution

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Radius of circle ` = 15` cm
We can draw a diagram with the given details.
Please refer to video for the diagram.
We are given, `/_ AOB = 60^@`
As, `OA =OB`
`:.` Remaining angles in `Delta OAB` will be equal and `60^@` each.
So, `Delta OAB` will be equilateral triangle.
`:.` Area of `Delta AOB = sqrt3/4*OA^2 = sqrt3/4*15*15 = 97.3125 cm^2`
Now, area of circle `= pir^2 = 3.14*15*15 = 766.5 cm^2`
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