" I.let "g(x)=xf(x)," where "f(x)={x sin((1)/(x)),quad x!=0

If g(x)=xf(x), where f(x)={x sin((1)/(x));x!=00;x=0} then at x=0

Let g(x)=xf(x) , where f(x)={{:(x^(2)sin.(1)/(x),":",x ne0),(0,":",x=0):} . At x=0 ,

Let g(x)=xf(x) , where f(x)={{:(x^(2)sin.(1)/(x),":",x ne0),(0,":",x=0):} . At x=0 ,

g(x)=xf(x) , where f(x)=x"sin"(1)/(x),x!=0=0,x=0 . At x=0 :

Let h(x)=f(x)=f_(x)-g_(x) , where f_(x)=sin^(4)pix and g(x)=In x . Let x_(0),x_(1),x_(2) , ....,x_(n+1_ be the roots of f_(x)=g_(x) in increasing order. In the above question, the value of n is

Let h(x)=f(x)-g(x) , where f(x)=sin^(4)pix and g(x)=log x . Let x_(0),x_(1),x_(2) , ....,x_(n+1_ be the roots of f(x)=g(x) in increasing order. In the above question, the value of n is

Let f(x)=(2x+1)/(x),x!=0, where

Let f,g:R rarr R be two function diffinite f(x)={x sin((1)/(x)),x!=0; and 0,x=0 and g(x)=xf(x)