Delta=|[1,a,bc],[1,b,c],[1,c,ab]|

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Evaluate : triangle = |[1,a,bc],[1,b,ca],[1,c,ab]|

Evaluate: |[1,a,bc],[1,b,ca],[1,c,ab]|

Prove that |[1,a,bc] , [1,b,ca], [1,c,ab]|=|[1,a,a^2] , [1,b,b^2] , [1,c,c^2]|

Show that abs [[1,a,bc],[1,b,ac],[1,c,ab]]=(a-b)(b-c)(c-a)

Evaluate abs[[1,a,bc],[1,b,ca],[1,c,ab]]-abs[[1,a,b^2],[1,b,b^2],[1,c,c^2]]

|[1,a,bc] , [1,b,ca] , [1,c,ab]|=

Evaluate [[1,a,bc],[1,b,ca],[1,c,ab]]-[[1,a,a^2],[1,b,b^2],[1,c,c^2]]

Using properties of determinants prove the following. abs[[1,a,bc],[1,b,ca],[1,c,ab]]=(a-b)(b-c)(c-a)

Delta=det[[1,a,bc1,b,ca1,c,ab]]

Evaluate Delta -|(1,a,bc),(1,b,ca),(1,c,ab)|