[" (4).In an amino acid,the "],[" sumcanboryl group "],[" ionises at "pka_(1)=2.34],[" and ammonium ion at "],[pka_(2)=9.60" .The isoelectin "],[" poin tot the amin a acid "],[" is at ph."]

In an amino acid, the carboxyl group ionises at pK_(a1) = 2.34 and ammonium ion at pK_(a2) = 9.60 . The isoelectric point of the amino acid is at pH

In an amino acid the Carboxylic group ionises at p^(Ka_(1))=2.40 and Ammonium ion at p_(Ka_(2))=9.60 then the isoelectric point is ?

Carboxylic acid and amino groups of an amino acid are ionised at pK_(a_(1))= 2.34 and pK_(a_(2)) = 9.60 . The pH at which the amino acid will attain its isoelectric point is-

[" Incorrect statement among "],[" the following is "],[qquad [" The pKa of - COOH group in "],[" an a-amino acid is lower "],[" than the pKa of acetic acid."]],[" Proline is an example of "],[" aromatic heterocyclic ring "],[" containing amino acids "],[" There is two chiral centres "],[" in Leucine "],[" All naturally available amino "],[" acids are essential amino "],[" acids "]

Both amino group and carboxylic group are in ionised form in alpha acid at pH

The pKa values for the three acidic group P,Q,R are 4.3, 9.7 and 2.2 respectively, Calculate the isoelectric point of the amino acid?