A particle is placed at the lowest point of a smooth wire frame in the shape of a parabola, lying in the vertical xy-plane having equatioin `x^(2)`=5y(x,y are in meter). After slight displacement, the particle is set free. Find angular frequency of osciallation (in rad/sec) (Take g=10 m/`s^(2))`

A smooth wire frasme is in the shape of a parabola y = 5x^(2) . It is being rotated about y-axis with an angular velocity omega . A small bead of mass (m = 1 kg) is at point P and is in equilibrium with respect to the frame. Then the angular velocity omega is (g = 10 m//s^(2))

A smooth wire frasme is in the shape of a parabola y = 5x^(2) . It is being rotated about y-axis with an angular velocity omega . A small bead of mass (m = 1 kg) is at point P and is in equilibrium with respect to the frame. Then the angular velocity omega is (g = 10 m//s^(2))

A particle is gien a displacement of 4 m in the xy-plane.If the x-component of the displacement vector is 2 m,the y-component wll be:

A particle of mass 1 mg and charge q is lying at the mid-point of two stationary particles kept at a distance '2 m' when each is carrying same charge 'q'. If the free charged particle is displaced from its equilibrium position through distance 'x' (x lt lt 1" m") . The particle executes SHM. Its angular frequency of oscillation will be __________ xx10^(5) rad/s if q^(2)=10C^(2)

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Range OA is :-