A composite inclined plane has three different inclined surfaces `AB, BC` and `CD` of heights `1 m` each and coefficients of friction `(1)/(sqrt(3)), (1)/(sqrt(8))` and `(1)/(sqrt(15))` respectively. A particle given an initial velocity at `A` along `AB` transverses the inclined surfaces with uniform speed, reaches `D` in `5s`. The initial speed given is `("in" m//s)`

An engine of one metric ton is going up an inclined plane, 1 in 2 at the rate of 36 kmph. If the coefficient of friction is 1//sqrt(3) , the power of engine is

An engine of one metric ton is going up an inclined plane, 1 in 2 at the rate of 36 kmph. If the coefficient of friction is 1//sqrt(3) , the power of engine is

A body of mass 10 kg is placed on an inclined surface of angle 30^(@) . If coefficient of limiting friction is 1 //sqrt3 , find the inclined plane. Force is being exerted parallel to the inclined plane .

The speed of a particle changes from sqrt(5) ms^(-1) to 2sqrt(5) ms^(-1) in a time t . The magnitude of change in its velocity is 5 ms^(-1) the angle between the initial and final velocities of the particle is

The coefficient of friction for an inclined plane and a biock is (1)/sqrt(3) what is the acceleration of the block when angle of inclination of the plane is 30^(@) ?

Two blocks of masses 2kg and M are at rest on an inclined plane and are separated by a distance of 6.0m as shown. The coefficient of friction between each block and the inclined plane is 0.25 . The 2kg block is given a velocity of 10.0m//s up the inclined plane. It collides with M, comes back and has a velocity of 1.0m//s when it reaches its initial position. The other block M after the collision moves 0.5m up and comes to rest. Calculate the coefficient of restitution between the blocks and the mass of the block M. [Take sintheta=tantheta=0.05 and g=10m//s^2 ]

Two blocks of masses 2kg and M are at rest on an inclined plane and are separated by a distance of 6.0m as shown. The coefficient of friction between each block and the inclined plane is 0.25 . The 2kg block is given a velocity of 10.0m//s up the inclined plane. It collides with M, comes back and has a velocity of 1.0m//s when it reaches its initial position. The other block M after the collision moves 0.5m up and comes to rest. Calculate the coefficient of restitution between the blocks and the mass of the block M. [Take sintheta=tantheta=0.05 and g=10m//s^2 ]

Two blocks of masses 2kg and M are at rest on an inclined plane and are separated by a distance of 6.0m as shown. The coefficient of friction between each block and the inclined plane is 0.25 . The 2kg block is given a velocity of 10.0m//s up the inclined plane. It collides with M, comes back and has a velocity of 1.0m//s when it reaches its initial position. The other block M after the collision moves 0.5m up and comes to rest. Calculate the coefficient of restitution between the blocks and the mass of the block M. [Take sintheta=tantheta=0.05 and g=10m//s^2 ]