[" Area of "Delta ABC=20" sq units and its vertices "A" and "B],[" are "(-5,0)" and "(3,0)" ,respectively,If its vertex "C" lies "],[" on the line "x-y=2" ,then "C" is "]

The area of Delta ABC IS 5 sq units. Two of its vertices are A(2,1) and B(3,-2) . Third vertex C lies on the line given by y=x + 3 . Find the coordinates of C.

The area of a triangle is 3/2 square units. Two of its vertices are the points A (2, -3) and B(3,-2) , the third vertex of the triangle lies on the line 3x - y -2 = 0 , then third vertex C is

The area of a triangle is (3)/(2) square units.Two of its vertices are the points A(2,-3) and B(3,-2), the centroid of the triangle lies on the line 3x-y-2=0, then third vertex C is

The area of a triangle is 3/2 square units. Two of its vertices are the points A (2, -3) and B(3,-2) , the centroid of the triangle lies on the line 3x - y -2 = 0 , then third vertex C is

The area of triangle A B C is 20c m^2dot The coordinates of vertex A are -5,0) and those of B are (3,0)dot The vertex C lies on the line x-y=2 . The coordinates of C are (a) (5,3) (b) (-3,-5) (-5,-7) (d) (7,5)

The area of triangle A B C is 20c m^2dot The coordinates of vertex A are -5,0) and those of B are (3,0)dot The vertex C lies on the line x-y=2 . The coordinates of C are (5,3) (b) (-3,-5) (-5,-7) (d) (7,5)

The area of triangle A B C is 20c m^2dot The coordinates of vertex A are (-5,0) and those of B are (3,0)dot The vertex C lies on the line x-y=2 . The coordinates of C are (a) (5,3) (b) (-3,-5) (-5,-7) (d) (7,5)

The area of triangle ABC is 20cm^(2) .The coordinates of vertex A are -5,0 ) and those of B are (3,0). The vertex C lies on the line x-y=2. The coordinates of C are (5,3)(b)(-3,-5)(-5,-7)(d)(7,5)