[" Prove a "=sqrt(K_(P))" for "PCl_(5)simeq PCl_(3)+Cl_(2)" where "alpha" is degree of dissociation at temperature whe "],[" equilbrium constant is "K_(8)" ."]

Prove alpha=sqrt((K_(p)/(P+K_(p)))) for PCl_(5) hArr PCl_(3)+Cl_(2) where alpha is the degree of dissociation at temperature when equilibrium constant is K_(p) .

Prove alpha=sqrt((K_(p)/(P+K_(p)))) for PCl_(5) hArr PCl_(3)+Cl_(2) where alpha is the degree of dissociation at temperature when equilibrium constant is K_(p) .

For the reaction PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) , the equation connecting the degree of dissociation (alpha) of PCl_(5)(g) with the equilibrium constant K_(p) is

For the reaction PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) , the equation connecting the degree of dissociation (alpha) of PCl_(5)(g) with the equilibrium constant K_(p) is

In the dissociation of PCl_(5) as PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) If the degree of dissociation is alpha at equilibrium pressure P, then the equilibrium constant for the reaction is

In the dissociation of PCl_(5) as PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) If the degree of dissociation is alpha at equilibrium pressure P, then the equilibrium constant for the reaction is

The Vapour Density of mixture of PCl_(5), PCl_(3) and Cl_(2) is 92. Find the degree of dissociation of PCl_(5) .

In the reaction, PCl_(5)hArrPCl_(3)+Cl_(2) , the amounts of PCl_(5) , PCl_(3) and Cl_(2) , 2 moles each at equilibrium and the total pressure is 3 atm . Find the equilibrium constant K_(p) .