[" If "75g" of water at "100^(@)C" is added to "20],[" g of ice at "-15^(@)C" ,determine the "],[" resulting temperature.Given that "],[" latent heat of ice "=80calg^(-1)" and "],[" specific heat of ice = "0.5calg^(@)C^(-1)" ) "]

75 g of water at 100^@ C is added to 20 g of ice at -15^@C . Calculate the resulting temperature, give that latent heat of ice= 80 cal g^(-1)C^(-1) and specific heat of ice=0.5 cal g^(-1) C^(-1) .

The water of mass 75 g at 100^(@)C is added to ice of mass 20 g at -15^(@)C . What is the resulting temperature. Latent heat of ice = 80 cal//g and specific heat of ice = 0.5 .

20 g of steam at 100^@ C is passes into 100 g of ice at 0^@C . Find the resultant temperature if latent heat if steam is 540 cal//g ,latent heat of ice is 80 cal//g and specific heat of water is 1 cal//g^@C .

50 g of steam at 100^@ C is passed into 250 g of at 0^@ C . Find the resultant temperature (if latent heat of steam is 540 cal//g , latent heat of ice is 80 cal//g and specific heat of water is 1 cal//g -.^@ C ).

20g of steam at 100^(@) C is passed into 100g of ice at 0^(0) C. Find the resultant temperature if specific latent heat of steam is 540 callg., specific latent heat of ice is 80 cal/g and specific heat of water is 1 cal/ g^(0) C .