[Zn+1/2O_(2)rarr ZnOquad Delta H=-84000cal...(i)],[Hg+1/2O_(2)rarr HgOquad Delta H=-21700cal...(iil)],[" The heat of reaction: "],[(Delta H)" for,"Zn+HgO rarr ZnO+Hg" is - "]

Givecn that : Zn+1//2O_(2)rarr ZnO+84000 cal ……………1 Hg+1//2O_(2)rarr HgO+21700 cal …………2 The heat of reaction (Delta H) for, Zn+HgO rarr ZnO+Hg is :-

Givecn that : Zn+1//2O_(2)rarr ZnO+84000 cal ……………1 Hg+1//2O_(2)rarr HgO+21700 cal …………2 The heat of reaction (Delta H) for, Zn+HgO rarr ZnO+Hg is :-

From the thermochemical reactions, C(grap hite)+1//2O_(2)rarr CO , Delta H =-110.5 KJ CO+1//2O_(2)rarr CO_(2),Delta H=-283.2 KJ The heat of reaction of C(graph ite) +O_(2)rarr CO_(2) is :

From the thermochemical reactions, C(graphite) +1//2O_(2)rarr CO , Delta H = -110.5 KJ CO+1//2O_(2)rarr CO_(2),Delta H=-283.2 KJ the heat of reaction of C(graphite) +O_(2)rarr CO_(2) is :

Given that Zn+1/2 O_(2) rarr ZnO+35.25 kJ . HgO rarr Hg +1/2 O_(2) -9.11 kJ . The heat of the reaction Zn+HgO rarr ZnO +Hg is

C+O_(2)rarr CO_(2), Delta H = -94 K.cal, CO+(1)/(2)O_(2) rarr CO_(2), Delta H = -67.7 K.cal . On the basis of the above data, the heat of formation of 'CO' is

C_(2)H_(2) + 5/2 O_2(2) rarr 2CO_(2) + H_(2)O , Delta H = -310 kcal C + O_(2) rarr CO_(2) , " "Delta H = -94 kcal H_(2) + 1/2 O_(2) rarr H_(2)O, " " Delta H = -68 kcal On the basis of the above equations, DeltaH_(f) (enthalpy of formation) of C_2H_2 will be :

C_(2)H_(2) + 5/2 O_2(2) rarr 2CO_(2) + H_(2)O , Delta H = -310 kcal C + O_(2) rarr CO_(2) , " "Delta H = -94 kcal H_(2) + 1/2 O_(2) rarr H_(2)O, " " Delta H = -68 kcal On the basis of the above equations, DeltaH_(f) (enthalpy of formation) of C_2H_2 will be :

The heats of oxidation of Mg and Fe are given: Mg+1/2O_2 rarr MgO,Delta H=-145700 cal 2Fe+3/2O_2 rarr Fe_2O_3, Delta H=-193500 cal calculate the heat produced in the reaction 3 Mg+Fe_2O_3=3MgO+2Fe