[" Q.1: The hardness of a water sample (in terms of equivalents of "CaCO_(3))" containing "],[10^(-3)M" CaSO,is: (molar mass of "CaSO_(4)=136g/mol" )."],[" Answer ":100ppm]

the hardness of a water sample (in terms of Equivalents of CaCO_(3) ) containing 10^(-3)MCaSO_(4) Is : (Molar mass of CaSO_(4)=136 gmol^(-1) )

the hardness of a water sample (in terms of Equivalents of CaCO_(3) ) containing 10^(-3)MCaSO_(4) Is : (Molar mass of CaSO_(4)=1365g mol^(-1) )

the hardness of a water sample (in terms of Equivalents of CaCO_(3) ) containing 10^(-3)MCaSO_(4) Is : (Molar mass of CaSO_(4)=1365h mol^(-1) )

Hardness of a water sample is 100 "ppm" CaCo_(3) . Thus molarity of CaCO_(3) is

100 mL of a water sample contains 0.81g of calcium bicarbonate and 0.73g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalent of CaCo_3 is 10^x ppm. What is numerical value of x? (molar mass of calcium bicarbonate is 162 gmol^(-1) and magnesium bicarbonate is 146g mol^(-1))

100 mL of a water sample contains 0.81g of calcium bicarbonate and 0.73g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalent of CaCo_3 is 10^x ppm. What is numerical value of x? (molar mass of calcium bicarbonate is 162 gmol^(-1) and magnesium bicarbonate is 146g mol^(-1))

100 mL of a water sample contains 0.81g of calcium bicarbonate and 0.73g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalent of CaCo_3 is 10^x ppm. What is numerical value of x? (molar mass of calcium bicarbonate is 162 gmol^(-1) and magnesium bicarbonate is 146g mol^(-1))

Hardness of water sample is 300 ppm CaCO_3 Hence its molarity is:

Hardness of water sample is 300 ppm CaCO_3 Hence its molarity is: