" If "f(x)=tan x+tan^(2)x tan2x" and "^(g(n))=sum_(n=1)^(oo)f(2^(2))

If f(x)=tan x+tan^(2)x tan2x and g(n)=sum_(r=0)^(n)f(2^(r)) and l=g(2015)-tan(2^(201) then

If f(x)=tan x+tan^(2)x tan2x and g(n)=sum_(r=0)^(x=k)f(2^(r)) then g(2013)-tan(2^(2014)) is equal to ( )0(B) tan 1(C)-tan1(D)1

f(x)=tan^(n)X-(1/2)In x. Then

If f(x)=(2tan x)/(1+tan^(2)x) then value of f((pi)/(4)) will be

If f(x)=sec^(2)x then (1+tan A*tan B)^(2)+(tan A-tan B)^(2)=

If f(x) = lim_(n->oo) tan^(-1) (4n^2(1-cos(x/n))) and g(x) = lim_(n->oo) n^2/2 ln cos(2x/n) then lim_(x->0) (e^(-2g(x)) -e^(f(x)))/(x^6) equals

f(x)=tan(x/2)sec x+tan(x/2^(2))sec(x/2)+tan(x/2^(3))sec(x/2^(2))+.....+tan(x/2^(n))*sec(x/2^(n-1)) and g(x)=f(x)+tan((x)/(2^(n))) where x in(-(pi)/(2),(pi)/(2)) and n in N then g(x) is

The period of f(x)=sin x + tan (x/2) + sin (x/2^(2))+tan (x/2^(3))+ ------- + sin ((x)/(2^(n-1)))+tan((x)/(2^(n)))

If f(x)=int((1-ln(tan^(-1)x))/(1+(ln(tan^(-1)x))^(2)))^(2)(dx)/(1+x^(2)) then f(tan1)-f(tan(1)/(e)) is equal to