A particle executes SHM according to equation `x=10(cm)cos[2pit+(pi)/(2)]`, where t is in seconds. The magnitude of the velocity of the particle at `t=(1)/(6)s` will be :-

A particle executes simple harmonic motion according to the displacement equation y = 10 cos(2 pi t + (pi)/(6))cm where t is in second The velocity of the particle at t = 1/6 second will be

A particle is performing SHM according to the equation x=(3cm)sin((2pit)/(18)+(pi)/(6)) , where t is in seconds. The distance travelled by the particle in 39 s is

A particle is performing SHM according to the equation x=(3cm)sin((2pi)/(18)+(pi)/(6)) , where t is in seconds. The distance travelled by the particle in 39 s is

A particle executing SHM according to the equation x=5cos(2pit+(pi)/(4)) in SI units. The displacement and acceleration of the particle at t=1.5 s is

A particle executing SHM according to the equation x=5cos(2pit+(pi)/(4)) in SI units. The displacement and acceleration of the particle at t=1.5 s is

A particle executes SHM according to the equation, y=4sin( pi t+(pi)/(3)) ,where y is in m and t is in' s '.The phase of particle at time t=0 is

A particle Moves along x axis satisfying the equation x=[t(t+1)t-2 where t is in seconds and x is in Meters Then the Magnitude of initial velocity of the particle in M/s is

A particle is oscillating according to the equation x = 10cos2pit , where 't' is in seconds. The particle moves from the position of maximum displacement to equilibrium in time.

A particle osciallates with SHM according to the equation x= (2.5 m ) cos [ ( 2pi t ) + (pi)/(4)] . Its speed at t = 1.5 s is

A particle osciallates with SHM according to the equation x= (2.5 m ) cos [ ( 2pi t ) + (pi)/(4)] . Its speed at t = 1.5 s is