Calculate the energy released when three alpha particles combine to form a `^12 C` nucleus. The atomic mass of `_2^4 He` is `4.002603 u`.

Calculate the energy released when three alpha particles combine to form a _^12 C nucleus. The atomic mass of _^4 He is 4.002603 u .

Calculate the energy released when three alpha particles combine to form a _^12 C nucleus. The atomic mass of _^4 He is 4.002603 u .

Show that the energy released when three alpha particles fuse to form ""^(12)C is 7.27 MeV. The atomic mass of ""^(4)He is 4.0026u and that of ""^(12)C is 12.0000u.

Three prop -particles ( m_prop = 4.0026) amu are combined to form a C^12 nucleus. The energy released will be

Calculate the energy released in the alpha decay of ^238 Pu to ^234 U , the masses involved being m_Pu=238.04955u , m_U= 234.04095u and m_He =4.002603u