[" 63.Let "f(x)=x[x],x in z,[.]" is GlF "],[" then "f'(x)=],[" (A)2x "],[" (B) None "],[" (D)2[ textrmxx ] "]

Let f(x) = x[x], x in z, [.] is GIF then "f"^(')(x) =

[" 14.If "f(x)=(1-cos2x)/(x^(2))quad " (b) "x!=0" and "f(x)" is continuous at "x=0" ,then "f(0)=?],[[" (a) "1," (b) "2," (c) "3," (d) None of these "]]

[" 14.If "f(x)=(1*cos2x)/(x^(2))quad :x!=0" and "f(x)" is continuous at "x=0" ,then "f(0)=?],[[" (a) "1," (b) "2," (c) "3," (d) None of these "]]

f (x)=l n[x^(2)+x+1], where [.] GlF.

Let f(x) = 2x + 5. If x ne 0 then find (f (x +2) - f(2))/(x)

Let f(x)-2x-x^(2),x<=1 then the roots of the equation f(x)=f^(-1)(x) is

Let f(x)=max. {2-x,2,1+x} then int_(-1)^1 f(x)dx= (A) 0 (B) 2 (C) 9/2 (D) none of these

Let f(x)=max. {2-x,2,1+x} then int_(-1)^1 f(x)dx= (A) 0 (B) 2 (C) 9/2 (D) none of these

Let f(x) = (x^2 - x)/(x^2 + 2x) , then d/(dx) (f^(-1)(x))^(-) is equal to

Let f(x)={1+(2x)/a ,0lt=x 1)f(x) exists ,then a is (a) 1 (b) -1 (c) 2 (d) -2