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If ((1-3p))/2,((1+4p))/3,((1+p))/6 are t...

If `((1-3p))/2,((1+4p))/3,((1+p))/6` are the probabilities of three mutually excusing and exhaustive events, then the set of all values of `p` is a. (0,1) b. (-1/4,1/3) c. (0,1/3) d.

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