(x+tan y)dy=sin2ydx

Solve the following differential equations: (x+tany)dy=sin2ydx

Solve : (x+ tan y) dy = sin 2 y dx

[" 6.Let "y(x)" be the solution of the differential equation "dy+x sin2ydx=x^(3)cos^(2)ydx" and "],[y(0)=0" then "y(1)" is "],[[" 1) "tan^(-1)(1)," 2) "tan^(-1)(e)," 3) "tan^(-1)((2)/(e))," 4) "tan^(-1)((1)/(2e))]]

(x + ln y) dy + ydx = 0

Find integrating factor of (x+tany) dy = tan ydx