There is a microscope whose objective's numerical aperture is `sin alpha = 0.24`, where `alpha` is the half-angle subtended by the objective's rim. Find the minimum spearation resolved by this microscope when an object is illuminated by light with wavelength `lambda = 0.55 mu m`.

Find the minimum magnification of a microscope, whose objective's numerical apertune is sin alpha = 0.24 , at which the resolving power of the objective is totally employed if the diameter of the eye's pupil is d_(0) = 4.0mm .

A microscople has numberical apertune sin alpha = 0.12 , where alpha is the aperture angle subtended by the entrance pupil of the microscope. Assuming the diameter of an eye's pupil to be equal to d_(0) = 4.0 mm determine the microscope magnification at which (a) the diameter of the beam of light coming from the microscope is equal to the diameter of the eye's pupil, (b) the illuminance of the image on the retina is independent of magnification (consider the case when the beam of light passing through teh sysytem ''microscope-eye'' is bounded by the mounting of the objective).

What is the minimum distance between two objects which can be resolved by a microscope having the visual angle of 30^@ when light of wavelength 500 nm is used ?

There is a telescope whose objective has a diameter D = 5.0 cm . Find the resolving power of the objective and the minimum separation between two points at a distance l = 3.0km from the telescope, which it can resolve (assume lambda = 0.55 mu m) .

A microscope has an objective of aperture 8 mm and focal length of 5cm .The minimum separation between two objects to be just resolved by the microscope is (wavelength of light used = 5500 Å

A telescop with an objective aperture 0.25 m is uded to obseve two stars. If the wavelength of light used is 5000Å . Find the minimum angular sepration between them.