What is the product of the perpendiculars from the two points `(pm sqrt(b^(2)-a^(2)), 0)` to the line `ax cos phi + by sin phi =ab` ?

What is the product of the perpendicualars drawn from the point pm (sqrt(a^(2)-b^(2)),0) upon the line bx cos alpha + ay sin alpha =ab ?

The product of y the perpendiculars from the two points (pm 4, 0) to the line 3x cos phi +5y sin phi =15 is

The product of the perpendiculars drawn from the points pm sqrt(a^(2) -b^(2),0) on the line x/a cos theta+ y/b sin theta =1, is

Prove that the product of the length of the perpendiculars from the points (sqrt(a^2 -b^2) , 0) and (-sqrt(a^2 -b^2), 0) to the line x/a cos theta + y/a cos theta + y/b sin theta = 1 is

Foot of the perpendicular from origin to the line joining the points (a cos theta,a sin theta),(a cos phi,a sin phi) is

Find length of perpendicular from origin to the lines passes from points ( cos theta , sin theta ) and ( cos phi , sin phi) .