The lines `vecr=i-j-k+s(i+2j-2k)` and `vecr=(i-2j+3k)+t(-i+j-2k)`

The lines vec r=i-j-k+s(i+2j-2k) and vec r=(i-2j+3k)+t(-i+j-2k)

The lines vec r=(i+j+k)alpha+3k and vec r=(i-2j+k)beta+3k

The shortest distance between the lines r=(4i-j)+lambda(i+2j-3k) and r=(i-j+2k)+mu(2i+4j-5k) is

The length of the shortest distance between the two lines r=(-3i+6j)+s(-4i+3j+2k) and r=(-2i+7k)+t(-4i+j+k) is

Find the shortest distance between the lines barr=(2i-j-k)+lambda(3i-5j+2k) and barr=(i+2j+k)+mu(i-j+k)

Consider the lines barr=(i+2j-2k)+lambda(i+2j) and barr=(i+2j-2k)+mu(2j-k) Find a vector perpendicular to both the lines.

Consider the lines barr=(i+2j-2k)+lambda(i+2j) and barr=(i+2j-2k)+mu(2j-k) Find the angles between the lines.