In a triangle ABC, right angled at A, on the leg AC as diameter, a semicircle is described. If a chord joi A with the point of intersection D of the hypotenuse and the semicircle, then the length of AC equals to

In a triangle ABC, right angled at A, on the leg AC as diameter, semicircle is described. If a chord joins A with the point of intersection D of the hypotenuse and the semicircle, then the length of AC equals to

In a triangle ABC, right angled at A, on the leg AC as diameter,a semicircle is described. If a chord joins A with the point of intersection D of the hypotenuse and the semicircle,then the length of AC is equal to (AB.AD)/(sqrt(AB^(2)+AD^(2))) (b) (AB.AD)/(AB+AD)sqrt(AB.AD)(d)(AB.AD)/(sqrt(AB^(2)-AD^(2))) (b)

In a triangle A B C , right angled at A , on the leg A C as diameter, a semicircle is described. If a chord joins A with the point of intersection D of the hypotenuse and the semicircle, then the length of A C is equal to (A BdotA D)/(sqrt(A B^2+A D^2)) (b) (A BdotA D)/(A B+A D) sqrt(A BdotA D) (d) (A BdotA D)/(sqrt(A B^2-A D^2))

In a triangle A B C , right angled at A , on the leg A C as diameter, a semicircle is described. If a chord joins A with the point of intersection D of the hypotenuse and the semicircle, then the length of A C is equal to (a) (A B.A D)/(sqrt(A B^2+A D^2)) (b) (A B.A D)/(A B+A D) (c) sqrt(A B.A D) (d) (A B.A D)/(sqrt(A B^2-A D^2))

In a right triangle ABC ,right angled at A, on the leg AC as diameter,a semicircle is described.The chord joining A with the point of intersection D of the hypotenuse and the semicircle,then the length AC equals to

In a ΔABC, a semicircle is inscribed, whose diameter lies on the side c. Then find the radius of the semicircle.(Where Δ is the area of the triangle ABC)

AB is the diameter of a semicircle with length of radius 4 cm C is any point on the semicircle. If BC = 2sqrt7 cm then find the length of AC.

A right angle triangle whose hypotenuse is c and its perpendicular sides are a and b. Three semicircles are drawn along the three sides of this triangle in such a way that the diameter of each semicircle is equal to the length of the respective side of the triangle. The semicircle drawn wiht the help of hypotenuse intersects the other two semicircles as shown in the concerned diagram. Find the area of the shaded region.

In a ΔABC, a semicircle is inscribed, whose diameter lies on the side c. Then the radius of the semicircle is (Where Δ is the area of the triangle ABC)

In a Delta ABC, a semicircle is inscribed,whose diameter lies on the side c.Then the radius of the semicircle is (Where Delta is the area of the triangle ABC)