Find the distance covered by a particle from time `t = 0` to `t = 6` sec when the particle follow the movament according to `y = a cos ((pi)/(4))t`

Find the distance travelled by the particle during the time t = 0 to t = 3 second from the figure .

The distance travelled (in meters) by the particle from time t = 0 to t = t will be –

If the distance s travelled by a particle in time t is s=a sin t +b cos 2t , then the acceleration at t=0 is

The distance travelled by a particle in time t is gicen by s=t^3-2t^2-3t+5 . The velocity of the particle when t=2 sec is

Distance travelled by particle at any time t is given by S=t^(2)+6t+8 Speed of particle at any time t is

The distance covered by a particle in t sec is given by x=3+8t-4t^(2) . What will be its velocity after 1 second.

Show that the distance covered by a particle having uniform acceleration in time interval (t'-t) is the area under v - t graph for time t' and t.

The horizontal and vertical distances travelled by a particle in time t are given by x=6t and y=8t-5t^(2) . If g= 10m//sec^(2) , then the initial velocity of the particle is

Velocity of a particle varies with time as v=4t. Calculate the displacement of particle between t=2 to t=4 sec.