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x^2-25lt=0, x^2-9>0, xgeq-4=...

`x^2-25lt=0, x^2-9>0, xgeq-4=`

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cosα is a root of the equation 25x^2+5x−12=0,−1 lt x lt 0 , then find the value of sin2α is:

cosα is a root of the equation 25x^2+5x−12=0,−1 lt x lt 0 , then find the value of sin2α is:

cosα is a root of the equation 25x^2+5x−12=0,−1 lt x lt 0 , then find the value of sin2α is: