The line `x +3y -2= 0` bisects the angle between a pair of straight lines of which one has equation `x-7y + 5 = 0` ,then find equation of other line

the line x+3y-2=0 bisects the angle between a pair of straight lines of which one has equation x-7y + 5 = 0 . The equation of the other line is :

the line x+3y-2=0 bisects the angle between a pair of straight lines of which one has equation x-7y + 5 = 0 . The equation of the other line is : (A) 3x+3y-1=0 (B) x-3y+2=0 (C) 5x+5y-3=0 (D) None of these

the line x+3y-2=0 bisects the angle between a pair of straight lines of which one has equation x-7y + 5 = 0 . The equation of the other line is : (A) 3x+3y-1=0 (B) x-3y+2=0 (C) 5x+5y-3=0 (D) None of these

Find the angles between the pairs of straight line x-y sqrt(3)=5 and sqrt(3)x+y=7

The angle between the two straight line of a pair of straight line x^2 - y^2 - 2y - 1 = 0 is

Find the angles between the pairs of straight lines: x+sqrt(3)y-5=0\ a n d\ sqrt(3)x+y-7=0