If the sum of the deviations of 50 observations from 30 to 50, then mean of these observation is

If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is

If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is

If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is

If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is

If the algebraic sum of deviations of 20 observation from 30 is 20, then the mean of observation is :

The sum of deviations of ‘n’ observa tions from 25 is 25 and sum of devia tions of the same’n’ observations from 35 is-25. Find the mean of the observations.

The algebraic sum of the deviations of 20 observations measured from 30 is 2. What would be the mean of the observations?

The sum of deviations of n observations about 25 is 25 and sum of deviations of the same n observations about 35 is -25. Find the mean of the observations.

The sum of 20 observations of the deviation from 30 is 20. Their mean is

The sum of deviations of n observations about 25 is 25 and sum of deviations of the same n observations about 35 is -25 . The mean of observations is