Two particle of same time period `(T)` and amplitude undergo `SHM` along the same line with initial and phase of `pi//6`. If they start at the same point along the opposite. Directions. Find the time other which they will theel again for the first time

Two particle of same time period (T) and amplitude undergo SHM along the same line with initial and phase of pi//6 . If they start at the same point along the opposite directions. Find the time other which they will meet again for the first time

Time period (T) and amplitude (A) are same for two particle which undergoes SHM along the same line. At one particular instant one particle is at phase (3pi)/(2) and the other is at zero,while moving in the same direction. Find the time at which they will cross each other

Two particles execute SHM of same time period but different amplitudes along the same line. One starts from mean position having amplitude A and other starts from extreme position having amplitude 2A. Find out the time when they both will meet?

Two particles have time periods T and 5T/4. They start SHM at the same time from the mean postion. After how many oscillations of the particle having smaller time period, they will be again in the same phase ?

Two particles execute SHM of the same time period along the same straight lines. They cross each other at the mean position while going in opposite directions. Their phase difference is

Two particles undergo SHM along parallel lines with the same time period (T) and equal amplitudes. At particular instant, one particle is at its extreme position while the other is at its mean position. The move in the same direction. They will cross each other after a further time.

Two particles P_(1) and P_(2) are performing SHM along the same line about the same meabn position , initial they are at their position exterm position. If the time period of each particle is 12 sec and the difference of their amplitude is 12 cm then find the minimum time after which the seopration between the particle becomes 6 cm