The displacement function of a `S.H.M` is given by
`y = cos [(omega t + phi)]`
if at `t = 0` th displaxcement is `y = 1` on and velocity `cm s^(-1)` The value amplitude `(A in cm)` is

The displacement in S.H.M. is given by y= a sin (20t+4) . What is the displacement it is increased by 2pi//omega ?

The displacement of an object oscillating on a spring is given by x(t) = x_(m) cos (omega t+ phi) . If the initial displacement is zero and the initial velocity is in the negative x direction. Then the phase constant phi is

The displacement of a particle performing a S.H.M. is given by x =12 "cos" (omega t + alpha) cm . If at time t, the displacement of the particle is 6 cm, them the phase of the particle at that instant is

The displacement of SHM particle is x(t)= A cos (omega t+ phi) . Its initial displacement is 1 cm and initial velocity is pi(cm)/(sec) and angular frequency is pi s^(-1) . Find amplitude.

The displacement of a particle executing a S.H.M. is given by x= A "sin" omega t +A "cos" omega t . What is the amplitude of motion ?

The displacement of particle in S.H.M. May be given by y = a sin(omegat + phi) show that if the time t is increased by 2pi//omega , the value of y remains the same.