The coordinates of the vertices `Ba n dC` of a triangle `A B C` are (2, 0) and (8, 0), respectively. Vertex `A` is moving in such a way that `4tanB/2tanC/2=1.` Then find the locus of `A`

The coordinates of the vertices Ba n dC of a triangle A B C are (2, 0) and (8, 0), respectively. Vertex A is moving in such a way that 4tan(B/2)tan(C/2)=1. Then find the locus of A

The coordinates of the vertices B and C of a triangle ABC are (2,0) and (8,0), respectively.Vertex A is moving in such a way that 4tan(3)/(2)tan(C)/(2)=1. Then find the locus of A

Coordinates of the vertices B and C of a triangle ABC are (2,0) and (8,0) respectively.The vertex A is varying in such a way that 4tan((B)/(2))tan((C)/(2))=1 and locus of A is "((x-5)^(2))/(25)+(y^(2))/(k^(2))=1 ,then k=

The coordinates of vertices A and B of an equilateral triangle ABC are (- 4, 0) and (4, 0) respectively. Which of the following could be coordinates of C

B and C are the vertex of a triangle ABC with coordinate (2 , 0) and (8 , 0) respectively. Another vertex A moves in such a way that it satisfies the relation 4 " tan" (B)/(2) "tan" (C)/(2) = 1 . If the equation of locus of A is (x - 5)^(2)/5^2+ (y^(2))/(k^(2)) = 1 , then the value fo k is _

The coordinates of the vertices A, B and C of a triangle ABC are (0,5), (-1,-2) and (11,7) respectively . Find the coordinates of the foot of the perpendicular from B on AC.

The coordinate of the vertices B and C of the triangle ABC are (5,2,8) and (2, -3, 4) respectively, if the coordinates of the centroid of the triangle are (3, -1,3), then the coordinates of the vertex A are-

Find the coordinates of the third vertex of a triangle whose two vertices and centroid are (0,0),(5,6) and (0,3) respectively.

Base BC of triangle ABC is fixed and opposite vertex A moves in such a way that tan.(B)/(2)tan.(C)/(2) is constant. Prove that locus of vertex A is ellipse.