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Two opposite forcesF(1) = 120 N and F(2)...

Two opposite forces`F_(1) = 120 N` and `F_(2) = 80 N` act on an elastic plank of modulus of elasticity `Y= 2 x 10^(11) N//m^(2)` and length `l=1m` placed over a smooth horizontal surface. The cross-sectional area of the plank is `S = 0.5 m^(2)`. The change in length of the plank is `x xx 10^(-11)m`. Find the value of `x`.

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