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The equation of the circle having the...

The equation of the circle having the center on the line `x+2y-3=0` and passing through the point intersection of the circles `x^2+y^2-2x-4y+1=0a n dx^2+y^2-4x-2y+4=0` is `x^2+y^2-6x+7=0""` `x^2+y^2-3u-2y+4=0` `x^2+y^2-2x-2y+1=0` `x^2+y^2+2x-2y+4=0`

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The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^2+y^2-2x-4y+1=0a n dx^2+y^2-4x-2y+4=0 is

The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^(2)+y^(2)-2x-4y+1=0 and x^(2)+y^(2)-4x-2y+4=0 is

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The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^(2)+y^(2)-2x-4y+1=0andx^(2)+y^(2)-4x-2y+4=0 is x^(2)+y^(2)-6x+7=0x^(2)+y^(2)-3y+4=0 c.x^(2)+y^(2)-2x-2y+1=0x^(2)+y^(2)+2x-4y+4=0

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The point of tangency of the circles x^2+ y^2 - 2x-4y = 0 and x^2 + y^2-8y -4 = 0 , is