`XY_(2)` dissociates `XY_(2)(g) hArr XY(g)+Y(g)`. When the initial pressure of `XY_(2)` is `600` mm Hg, the total equilibrium pressure is `800` mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.

AB_(2) dissociates as : AB_(2 (g)) hArr AB_((g)) + B_((g)) When the intial pressure of AB_(2) is 500 mm Hg , the total equilibrium pressure is 700 mm Hg . Calculate equilibrium constant for the reaction , assuming that the volume of the system remains unchanged .

AB_(2) dissociates as AB_(2)(g) hArr AB(g)+B(g) . If the initial pressure is 500 mm of Hg and the total pressure at equilibrium is 700 mm of Hg. Calculate K_(p) for the reaction.

AB_(2) dissociates as AB_(2)(g) hArr AB(g)+B(g) . If the initial pressure is 500 mm of Hg and the total pressure at equilibrium is 700 mm of Hg. Calculate K_(p) for the reaction.

PQ_(2) dissociates as PQ_2 (g)hArrPQ(g)+Q(g) The initial pressure of PQ_2 is 600 mm Hg. At equilibrium, the total pressure is 800mm Hg. Calculate the value of K_p .

PQ_(2) dissociates as PQ_2 (g)hArrPQ(g)+Q(g) The initial pressure of PQ_2 is 600 mm Hg. At equilibrium, the total pressure is 800mm Hg. Calculate the value of K_p .