`(a+b)sinc/2=c cos((A-B)/2)`

For any triangle ABC, prove that (a+b)/c=(cos((A-B)/2))/(sinC/2)

For any triangle ABC, prove that (a+b)/c=(cos((A-B)/2))/(sinC/2)

If A+B+C=pi then prove cos( (A)/2) cos( (B-C)/2) + cos( B/2) cos((C-A)/2) + cos( C/2) cos( (A-B)/2) = sinA +sinB+sinC

If A+B+C+D=360^(@) then show that sinA-B+sinC-sinD= -4cos((A+B)/2)cos((A+D)/2)sin((A+C)/2)

If A+B+C = 2S , then prove that sin(S-A)+sin(S-B)+sinC = 4 cos ((S-A)/2) cos ((S-B)/2) sin C/2 .

If A+B+C=pi , prove that : sinA+sinB+sinC= 4cos( A/2 )cos( B/2) cos(C/2)

a(cos C-cos B)=2(b-c)cos^(2)(A)/(2)

If A+B+C=180 , prove that: sinA+sinB+sinC=4cos(A/2)cos(B/2)cos(C/2)

In triangleABC,A+B+C=pi ,show that sinA+sinB+sinC=4cos(A/2)cos(B/2)cos(C /2)