If `M_1` and `M_2` are the feet of perpendiculars from foci `F_1` and `F_2` of the ellipse `x^2/64+y^2/25=1` on the tangent at any point P of the ellipse then

If F_1" and "F_2 be the feet of perpendicular from the foci S_1" and "S_2 of an ellipse (x^2)/(5)+(y^2)/(3)=1 on the tangent at any point P on the ellipse then (S_1F_1)*(S_2F_2) is

If F_(1) and F_(2) are the feet of the perpendiculars from foci s_(1) and s_(2) of an ellipse 3x^(2)+5y^(2)=15 on the tangent at any point P on the ellipse then (s_(1)F_(1))(S_(2)F_(2)) =

If F_(1) and F_(2) are the feet of the perpendiculars from foci S_(1) and S_(2) of the ellipse (x^(2 /(25 +y^(2 /(16 =1 on the tangent at any point P of the ellipse,then the minimum value of S_(1 F_(1 +S_(2 F_(2 is 1) 2, 2) 3, 3) 6, 4) 8

If F_1 and F_2 are the feet of the perpendiculars from the foci S_1a n dS_2 of the ellipse (x^2)/(25)+(y^2)/(16)=1 on the tangent at any point P on the ellipse, then prove that S_1F_1+S_2F_2geq8.

If F_1 and F_2 are the feet of the perpendiculars from the foci S_1a n dS_2 of the ellipse (x^2)/(25)+(y^2)/(16)=1 on the tangent at any point P on the ellipse, then prove that S_1F_1+S_2F_2geq8.

If F_1 and F_2 are the feet of the perpendiculars from the foci S_1a n dS_2 of the ellipse (x^2)/(25)+(y^2)/(16)=1 on the tangent at any point P on the ellipse, then prove that S_1F_1+S_2F_2geq8.

If M_(1) and M_(2) are the feet of the perpendiculars from the foci S_(1) and S_(2) of the ellipse (x^(2))/(9)+(y^(2))/(16)=1 on the tangent at any point P on the ellipse, then (S_(1) M_(1)) (S_(2) M_(2))=

If F_(1) and F_(2) are the feet of the perpendiculars from the foci S_(1)andS_(2) of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 on the tangent at any point P on the ellipse,then prove that S_(1)F_(1)+S_(2)F_(2)>=8