Prove that the area of the parallelogram contained by the lines `4y-3x-a=0,3y-4x+a=0,4y-3x-3a=0,` and `3y-4x+2a=0` is `(2/7)a^2dot`

The area of the parallelogram formed by the lines 4y-3x-a=0, 3y-4x+a=0, 4y-3x-3a=0, 3y-4x+2a=0 is

Area of the parallelograms formed by the lines 4 y - 3 x-a=0, 3 y-4 x+a =0 4 y-3 x-3 a=0,3 y-4 x+2 a=0

Prove that the area of the parallelogram formed by the lines 3x-4y+a=0,\ 3x-4y+3a=0,\ 4x-3y-a=0 and 4x-3y-2a=0 is (2a^2)/7 sq. units

Prove that the area of the parallelogram formed by the lines 3x-4y+a=0,\ 3x-4y+3a=0,\ 4x-3y-a=0\ a n d \4x-3y-2a =0\ i s (2a^2)/7s qdotu n i t sdot

Show that the area of the parallelogram formed by the lines x+3y-a = 0 , 3x-2y+3a=0, x + 3y +4a = 0 and 3x + 2y + 7a = 0 is 20/11 a^(2) sq units/

The area of the parallelogram formed by the lines 2x-3y+a=0, 3x-2y-a=0, 2x-3y+3a=0 and 3x-2y-2a=0 in square units , is

The area of the parallelogram formed by the lines 3x+4y=7a;3x+4y=7b;4x+3y-7c and 4x+3y=7d is-

Prove that the diagonals of the parallelogram formed by the four lines 3x+y=0,3y+x=0,3x+y=4,3y+x=4 are at right angles.

The area of the parallelogram formed by lines 2x-y+3=0, 3x+4y-6=0,2x-y+9=0, 3x+4y+4=0 is (in sq units)