`(z + 5)^2 = z^2 + 25`

(z) / (5) = 25

If |z| = 2 and the locus of 5z-1 is the circle having radius 'a' and z_1^2 + z_2^2 - 2 z_1 z_2 cos theta = 0 then |z_1| : |z_2| =

Let z_(1), z_(2), z_(3) be the roots of iz^(3) + 5z^(2) - z + 5i = 0 , then |z_(1)| + |z_(2)| + |z_(3)| = _____________.

Simplify combining like terms: – z^2 + 13z^2 – 5z + 7z^3 – 15z

Given that z^2 - 10z + 25 = 9 , what is z?

If (x-3)^(2) + (y-5)^(2) + (z-4)^(2) = 0, then the value of (x^2)/(9) + (y^2)/(25) + (z^2)/(16) is

Eccentricity of conic |z - 5i| + |z + 5i| = 25 is ___________.

If Z_1 = -3 + 4i , Z_2 = 12 - 5i , prove that |z_1+z_2|<|z_1-z_2|

Let S = {z in C : |z - 2| = |z + 2i| = |z - 2i|} then sum_(z in S) |z + 1.5| is equal to _________

If z_1 = (4,5) and z_2 = (-3,2) , then frac{z_1}{z_2} equals