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The equation (x^2+x+1)^2+1=(x^2+x+1)(x^2...

The equation `(x^2+x+1)^2+1=(x^2+x+1)(x^2-x-5)` for `x in (-2,3)` will have number of solutions. `1` b. `2` c. `3` d. 0

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