For a first order reaction, show that the time required for `99%` completion is twice the time required for the completion of `90%` of reaction.

For a first order reaction , show that time required for 99% completion is twice the time required for the completion of 90% of reaction.

For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.

For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.

(a) For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction. (b) Rate constant 'K' of a reaction varies with temperature 'T' according to the equation : logK=logA-E_a/(2.303R)(1/T) Where E_a is the activation energy. When a graph is plotted for log k Vs 1/(T) a straight line with a slope of -4250 K is obtained. Calculate E_a for the reaction. ( R=8.314JK^(-1)mol^(-1) )

For a first order reaction, show that time required for 99 % completion is twice the time required for the completion of 90 % of reaction.

For a first order reaction , show that time required for 99% completion is twice the time requried for the completion of 90% of reaction.