The normal drawn to the ellipse `x^2/a^2+y^2/b^2=1` at the extremity of the latus rectum passes through the extremity of the minor axis. Eccentricity of this ellipse is equal to

The latus rectum of an ellipse is equal to one-half of its minor axis. The eccentricity of the ellipse is

If the latus-rectum of the ellipse is half the minor axis, then its eccentricity is :

If the normal at an end of a latus rectaum of an ellipse passes through an extremity of the minor axis then the eccentricity of the ellispe satisfies .

If the normal at an end of a latus rectaum of an ellipse passes through an extremity of the minor axis then the eccentricity of the ellispe satisfies .

If latus-rectum is one-third minor axis, then eccentricity of the ellipse is

If the normal at an end of a latus-rectum of an ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 passes through one extremity of the minor axis, show that the eccentricity of the ellipse is given by e = sqrt((sqrt5-1)/2)

The latus rectum of an ellipse is half of its minor axis. Its eccentricity is :

The latus rectum of an ellipse is half of its minor axis. Its eccentricity is :

If the normal at an end of a latus-rectum of an elipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 passes through one extremity of the minor axis,show that the eccentricity of the ellipse is given by e^(4)+e^(-1)=0