The normal at an end of a latus rectum of the ellipse `x^2/a^2 + y^2/b^2 = 1` passes through an end of the minor axis if (A) `e^4+e^2=1` (B) `e^3+e^2=1` (C) `e^2+e=1` (D) `e^3+e=1`

If the normal at one end of a latus rectum of the ellipse x^2/a^2+y^2/b^2=1 passes through one end of the minor axis, then show that e^4+e^2=1 [ e is the eccentricity of the ellipse]

If the normals at an end of a latus rectum of an ellipse passes through the other end of the minor axis, then prove that e^(4) + e^(2) =1.

If the normals at an end of a latus rectum of an ellipse passes through the other end of the minor axis, then prove that e^(4) + e^(2) =1.

If the normal at the end of latus rectum of an ellipse x^(2)//a^(2)+y^(2)//b^(2)=1 of eccentricity e passes through one end of the minor axis then e^(4)+e^(2)=

If the normal at one end of lotus rectum of an ellipse passes through one end of minor axis then prove that, e^(4)+e^(2)-1=0

Normal at one end of the latus rectum of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 passes through one end of minor axis, then e^(4)+e^(2)= ( where e is the eccentricity of the ellipse)

If the normal at an end of a latus-rectum of an ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 passes through one extremity of the minor axis, show that the eccentricity of the ellipse is given by e = sqrt((sqrt5-1)/2)