`f : N-> R` such that `f(x) =(2x-1)/2` and `g:Q->R` such that `g(x)=x+2` be two functions. Then `(gof)(3/2)` is equal to

f: N to R such that f(x) = (2x-1)/2 and g: Q to R such that g(x) =x+2 , be two functions. Then (gof)(3/2) is equal to:

Let f:N→R such that f(x)=(2x−1)/2 and g:Q→R such that g(x)=x+2 be two function. Then (gof)( 3/2) =?

f:N rarr R such that f(x)=(2x-1)/(2) and g:Q rarr R such that g(x)=x+2 be two functions.Then (gof)((3)/(2)) is equal to

Let f:N rarr R be the function defined by f(x)=(2x-1)/2 and g:Q rarr Q be another function defined by g(x)=x+2 then (gof)(3/2) is

Let f:N rarr R be the function defined by f(x)=(2x-1)/2 and g:Q rarr Q be another function defined by g(x)=x+2 then (gof)(3/2) is

Let f:R to R be defined by f(x)=x^(2) and g:R to R be defined by g(x)=x+5 . Then , (gof)(x) is equal to -

Let f : N rarr R be the function defined by f(x) = (2x-1)/(2) and g : Q rarr R be another function defined by g(x) = x + 2. Then (gof) ((3)/(2)) is

If f: N rarr R be the function defined by f(x) = (2x-1)/2 and g : Q rarr R be another function defined by g(x) = x+2 . Then , gof (3/2) is .......