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[" That temperater "],[" surroundings ar...

[" That temperater "],[" surroundings are not negligible,is your answer greater of sinanct trom "25^(@)C" to "10^(@)C" ? "],[" heat of the metal? "],[" How many grams of ice at "-14^(@)C" are needed to cool "200grams" of wallg? "],[" specific heat of ice "=0.5cal/g^(@)C" and latent heat of "ic=80cal/g" ? "],[" The temperature of equal masses of three different liquids "A,B" and "C" are "12^(@)C,19^(@)C" ,mixe "]

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How many gram of ice at -14^@C are needed to cool 200 gm of water from 25^@C to 10^@C . Specific heat of ice = 0.5 cal/gm ^@C and latent heat of ice = 80 cal/gm.

How many grams of ice at -14 .^(@)C are needed to cool 200 gram of water form 25 .^(@)C to 10 .^(@)C ? Take specific heat of ice =0.5 cal g^(-1) .^(@)C^(-1) and latant heat of ice = 80 cal g^(-1) .

10 gm of ice at – 20^(@)C is added to 10 gm of water at 50^(@)C . Specific heat of water = 1 cal//g–.^(@)C , specific heat of ice = 0.5 cal//gm-.^(@)C . Latent heat of ice = 80 cal/gm. Then resulting temperature is -

What amount of ice at -14^(@)C required to cool 200gg of water from 25^(@)C to 10CC? (Given C_("ice")=0.5cal/g.^(@)C,L_(f) for ice =80cal//g )

500 gms of water is to be cooled from 3.5^@C to 20^@C . How many grams of ice at -10^@C will be required for this purpose? Specific heat of ice = 0.5 cal g^(-1) ""^@C^(-1) Latent heat of ice = 80 cal g^(-1) ?

What will be the final temperature when 150 g of ice at 0^@C is mixed with 300 g of water at 50^@C . Specific heat of water =1 cal//g//^@C . Latent heat of fusion of ice =80 cal//g .

What will be the final temperature when 150 g of ice at 0^@C is mixed with 300 g of water at 50^@C . Specific heat of water =1 cal//g//^@C . Latent heat of fusion of ice =80 cal//g .

One gram of ice at 0^(@)C is added to 5 gram of water at 10^(@)C . If the latent heat of ice be 80 cal/g, then the final temperature of the mixture is -

1 of a steam at 100^@C melts how much ice at 0^@C ? ( Latent heat of ice=80 cal/g and latent heat of steam =540 cal/g )